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If sinA=3/5 then value of 2+2ten square A |
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Answer» Given,sinA= 3/5We know that ,sinA = perpendicular \\hypotenuseSo, P=3 and H=5 By Pythagoras therorm: H^2=P^2+B^2 B=√H2-P2 =√25-9 =√16 =4 A/Q =2+2tan^2A =2+2(P/B)^2 =2+2×(3/4) ^2 =2+2×9/16 =2+9/8 =25/8 25/8 |
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