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If sinA+cosA=1 then secA+cosecA=?

Answer» {tex}SecA= 1/cos A and Cosec A= 1/Sin A{/tex}Sec A + Cosec A = 1/Cos A + 1/ Sin A = Sin A+ Cos A/Sin A. Cos A = 1/ SinA. Cos A as SinA+ Cos A= 1 (Given) = Sec A. Cosec A
secA×cosecA


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