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If sinA+cosA=√2,then evaluate tanA+cotA |
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Answer» let A=45,sin45+cos45=1/root2+1/root2,root2 common,so1+1/root2=》2/root2 BT RATIONALISATION,2/root2 ×root2/root2 =2*root2/2=root2these tells A=45tanA+cotA=tan45+cot45 =》1+1=2hence tanA+cotA=2 SinA + cosB =\xa0{tex}\\sqrt2{/tex}squaring both sides,1+2sinA*sinB = 2sin2A = 1{tex}\\Rightarrow{/tex} 2A = 90°A=45°tanA + cotA = tan45° + cot45°= 1 + 1 = 2 (ans) |
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