If sinA +cosA=m, secA+cosecA=n, then prove that n(m×m-1)=2m

1.	If sinA +cosA=m, secA+cosecA=n, then prove that n(m×m-1)=2m
Answer» SecA+cosecA(sinA+cosA-1)(sinA+cosA+1)=(sin^2A+cos^A+2sinAcosA-1)(secA+cosecA)=(1+2sinAcosA-1)(secA+ cosecA)={2sinAcosA×(1/cosA)}+{2sinAcosA×(1/cosA)}=2sinA+2cosA=2(sinA+cosA)=2m

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