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If sum and product of zeroes given 1/4,-1 respectively find its quadratic polynomial how do we find

Answer» Sorry the first two lines be like that ?let the two zeroes be in the form of alpha and beeta.
Use formula x^2 - (a+b)x + (a×b) =0___X^2 - (1/4)x + (-1)=0 ____ take 1/ 4 comon____ 1/4(4x^2 - x - 4 )=0 ____ 4x^2 - x - 4=0
Let the sum of zeroes be alpha and product of zeroes be beeta.... Then A/Q, alpha+beeta=1/4 and alphaXbeeta=-1... Now put sum and product in these ? x²-(alpha+beeta)x+alpha.beeta......we get,x²-1/4x+(-1)..i,e. the required polynomial is x²-1/4x-1.


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