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If sum ` log_(2)x+log_(4) x + log_(16) x + log_(256) x + …=6,` then find the value of x. |
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Answer» `log_(2)x+log_(4)x+log_(16)x+log_(32)x+ * * * = 6` ` rArr log_(2) x+ log_(2^(2))x+log_(2^(4))x+log_(2^(5))x+ * * * = 6` `rArr (1+1/2+1/4+1/8+...)log_(2) x= 6` ` rArr 1/(1-1/2)log_(2) x = 6` ` rArr log_(2) x = 3` ` rArr x = 8` |
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