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| 1. |
If tan A = 3\\4 and A+B=90°, then what is the value of cot B? |
| Answer» tan A =\xa0{tex}\\frac 34{/tex}cot A={tex}\\frac{4}{3}{/tex}A + B = 90o\xa0{tex}\\Rightarrow{/tex}\xa0A=90o-B{tex}\\Rightarrow{/tex}\xa0cot A=cot(90o-B){tex}\\Rightarrow{/tex}\xa0cot A=tan B{tex}\\Rightarrow{/tex}\xa0cotA = tanB =\xa0{tex}\\frac{4}{3}{/tex}{tex}\\Rightarrow{/tex}\xa0cot B =\xa0{tex}\\frac 34{/tex} | |