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If tan(A+B)=√3 and tan (A+B)= 1\\√3;0° |
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Answer» Tan(A+B)=√3. Tan(A-B)=1/√3Tan(A+B)=Tan60°. Tan(A-B)=tan30°A+B=60°. A-B=30° A+B=60° A-B=30° 2A=90° A=45° A+B=60° 45°+B=60° B=60°-45° B=15° tan(A+B)=tan 60\' so A+B=60 similarly Tan(A+B) =tan30\' so A + B =30 now solve these equations you will get answers |
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