If tan(A+B) =√3 and Tan(A-B) = 1/√3, where A and B are acute angle. Find them

If tan(A+B) =√3 and Tan(A-B) = 1/√3, where A and B are acute angle

1.	If tan(A+B) =√3 and Tan(A-B) = 1/√3, where A and B are acute angle. Find them
Answer» Tan (A+B) = √3Since tan 60 = √3 Therefore A+B = 60°Tan A- B= 1/√3 A -B = 30 Therefore by elimination method2A = 90=> A = 45 B = 15