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| 1. |
If tan alpha =5/12 find the value of sec alpha |
| Answer» According to the question,\xa0tan\xa0{tex}\\alpha{/tex}\xa0=\xa0{tex}\\frac{5}{12}{/tex}We know that, sec\xa0{tex}\\alpha{/tex}\xa0=\xa0{tex}\\sqrt{1 + tan^2 \\alpha}{/tex}=\xa0{tex}\\sqrt{1 + \\frac{25}{144}}{/tex}\xa0={tex}\\sqrt{ \\frac{144+25}{144}}{/tex}={tex}\\sqrt{ \\frac{169}{144}}{/tex}=\xa0{tex}\\frac{13}{12}{/tex} | |