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| 1. |
If tan theta + 1upon tan theta=2 then find value of tan square theta + 1upon tan square theta |
| Answer» If tanA + 1/tanA = 2, find the value of tan²A + 1/tan²A.Squaring both sides, =) (tanA + 1/tanA)² = 2²=) tan²A + 1/tan²A + 2(tanA)(1/tanA) = 4=) tan²A + 1/tan²A + 2 = 4=) tan²A + 1/tan²A = 4-2=) tan²A + 1/tan²A = 2. | |