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    				| 1. | If `tan theta = (sin alpha - cos alpha) /(sin alpha + cos alpha)`, then `sin alpha+cos alpha` is | 
| Answer» `tan theta = ( sin alpha/cos alpha - 1)/(sin alpha/cos alpha + 1)` `tan theta = ( tan alpha - 1)/(tan alpha + 1)` `tan theta = ( tan alpha - tan (pi/4))/( 1 + tan alpha* tan(pi/4))` `tan theta = tan(alpha - pi/4)` `theta = alpha - pi/4` `alpha = theta + pi/4` now,`sin(theta+ pi/4) + cos(theta + pi/4)` `= sin theta 1/sqrt2 + cos theta 1/sqrt2 + 1/sqrt2 cos theta - 1/sqrt2 sin theta` `= 2*1/sqrt2 cos theta` `= sqrt2 cos theta` option 2 is correct | |