If tan theta +sin theta =m and tan theta--sin theta =n, show that m²-

1.	If tan theta +sin theta =m and tan theta--sin theta =n, show that m²-n²=4√mn.
Answer» LHS = (Tan thetha+sin theta)^2 - (Tan thetha+sin theta)^2 RHS=4√mn 4√(tan thetha+sin theta)(tan theta-sin theta) 4√(tan^2theta-sin^2theta) 4.√(sin^2theta/cos^2theta-sin^2theta) 4.√sin^2theta-sin^2theta cos^2theta/cos theta = 4.sin theta/cos theta.1√1-cos^2 theta= 4tan.√sin^2 theta = 4 tan theta sin theta.

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