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| 1. |
If tanA=0.75 find the value of sinA+cosA. |
| Answer» {tex}% MathType!MTEF!2!1!+-% feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGceaqabeaaciGG0b% Gaaiyyaiaac6gacaaMc8Uaamyqaiabg2da9iaaicdacaGGUaGaaG4n% aiaaiwdaaeaaciGG0bGaaiyyaiaac6gacaaMc8Uaamyqaiabg2da9m% aalaaabaGaaG4maaqaaiaaisdaaaaabaGaciiDaiaacggacaGGUbGa% amyqaiabg2da9maalaaabaGaamiCaiaadwgacaWGYbGaamiCaiaadw% gacaWGUbGaamizaiaadMgacaWGJbGaamyDaiaadYgacaWGHbGaamOC% aaqaaiaadkgacaWGHbGaam4CaiaadwgaaaaabaGaamiAaiabg2da9m% aakaaabaGaamiCamaaCaaaleqabaGaaGOmaaaakiabgUcaRiaadkga% daahaaWcbeqaaiaaikdaaaaabeaaaOqaaiaadIgacqGH9aqpdaGcaa% qaaiaaiodadaahaaWcbeqaaiaaikdaaaGccqGHRaWkcaaI0aWaaWba% aSqabeaacaaIYaaaaaqabaaakeaacaWGObGaeyypa0JaaGynaaaaaa!6AF2!\\eqalign{ & \\tan \\,A = 0.75 \\cr & \\tan \\,A = {3 \\over 4} \\cr & \\tan A = {{perpendicular} \\over {base}} \\cr & h = \\sqrt {{p^2} + {b^2}} \\cr & h = \\sqrt {{3^2} + {4^2}} \\cr & h = 5 \\cr} {/tex}{tex}% MathType!MTEF!2!1!+-% feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbuLwBLn% hiov2DGi1BTfMBaeXatLxBI9gBaerbd9wDYLwzYbItLDharqqtubsr% 4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqrFfpeea0xe9Lq-Jc9% vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0FirpepeKkFr0xfr-x% fr-xb9adbaqaaeGaciGaaiaabeqaamaabaabaaGceaqabeaaciGGZb% GaaiyAaiaac6gacaWGbbGaeyypa0ZaaSaaaeaacaWGWbaabaGaamiA% aaaacqGH9aqpdaWcaaqaaiaaiodaaeaacaaI1aaaaaqaaiGacogaca% GGVbGaai4CaiaaykW7caWGbbGaeyypa0ZaaSaaaeaacaWGIbaabaGa% amiAaaaacqGH9aqpdaWcaaqaaiaaisdaaeaacaaI1aaaaaqaaiGaco% hacaGGPbGaaiOBaiaaykW7caWGbbGaey4kaSIaci4yaiaac+gacaGG% ZbGaaGPaVlaadgeacqGH9aqpdaWcaaqaaiaaiodaaeaacaaI1aaaai% abgUcaRmaalaaabaGaaGinaaqaaiaaiwdaaaaabaGaci4CaiaacMga% caGGUbGaaGPaVlaadgeacqGHRaWkciGGJbGaai4BaiaacohacaaMc8% Uaamyqaiabg2da9maalaaabaGaaG4naaqaaiaaiwdaaaaaaaa!67BD!\\eqalign{ & \\sin A = {p \\over h} = {3 \\over 5} \\cr & \\cos \\,A = {b \\over h} = {4 \\over 5} \\cr & \\sin \\,A + \\cos \\,A = {3 \\over 5} + {4 \\over 5} \\cr & \\sin \\,A + \\cos \\,A = {7 \\over 5} \\cr} {/tex} | |