1.

If `tantheta=(4)/(3)`, then find the value of `(3sintheta-2costheta)/(3sintheta+5costheta)`

Answer» `(3sintheta-2costheta)/(3sintheta+5costheta)= (3(sintheta)/(costheta)-2 (costheta)/(costheta))/(3(sintheta)/(costheta)+5(costheta)/(costheta))` (divedenumerator and denominator by `costheta`)
`=(3tantheta-2)/(3tantheta+5)=(3xx(4)/(3)-2)/(3xx(4)/(3)+5)=(4-2)/(4+5)=(2)/(9)`


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