If the area of triangle with vertices (x,0);(1,1)&(0,-2) is 4 sq units then the value of x is....

If the area of triangle with vertices (x,0);(1,1)&(0,-2) is 4 sq units

1.	If the area of triangle with vertices (x,0);(1,1)&(0,-2) is 4 sq units then the value of x is....
Answer» area of ∆ABC is 4x1 = xx2 = 1x3 = 0y1 = 0y2 = 1y3 = 2• area of ∆ABC :-{tex}= \\frac{1}{2} ( x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)){/tex}{tex}4 = \\frac{1}{2} (x(1 - 2) + 1(2 - 0) + 0(0 - 1)){/tex}8 = x - 2x + 28 - 2 = - x6 = - xx = - 6So, the value of x is ( - 6 )