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| 1. |
If the common difference of an A.P is, find a6_a12 |
| Answer» Let the first term of an A.P be {tex} a{/tex}, common difference {tex}d{/tex},{tex}d = - 6{/tex}an = a + (n -1)da16 = a + (16 - 1)(- 6)= a + (15)(- 6)= a - 90a12\xa0= a + (12 - 1)(-6 )= a + 11(-6)= a - 66a16\xa0-a12 = (a- 90) - ( a - 66)= a - 90 - a + 66= - 24 | |