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If the distance of two points are(4andK) and(1and0) is 5 find the value of k |
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Answer» points are (4,k) and (1,0)distance d2=(4-1)2+k2=52=25or 32+k2-=25k2\xa0=16So K= -4\xa0or 4 By applying distance formula , find AB.the value of k is 4 |
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