If the equation `2^x+4^y=2^y`is solved for `y`in terms of `x`where `x

1.	If the equation `2^x+4^y=2^y`is solved for `y`in terms of `x`where `x
Answer» Correct Answer - B `2^(2y) - 2^(y) + 2^(x) (1-2)^(x)) = 0` Putting ` 2^(y) = t`, we get ` t^(2) - t+2^(x) (1-2^(x)) = 0 ," where "t_(1) = 2^(y_(1)) and t_(2) = 2^(y_(2))` ` t_(1)t_(2)=2^(x)(1-2^(x))` ` 2^(y_(1)+y_(2))=2^(x) (1-2^(x))` ` y_(1)+y_(2) = x + log _(2) (1-2^(x))`

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