If the graph of the equation 4x + 3y = 12, has x = k – 3, and y = 5k – 1, find k.

If the graph of the equation 4x + 3y = 12, has x = k – 3, and y = 5k

1.	If the graph of the equation 4x + 3y = 12, has x = k – 3, and y = 5k – 1, find k.
Answer» 4x + 3y = 12. 4 (k - 3) + 3 (5k - 1) = 12. 4k - 12 + 15k - 3 = 12. 19k - 15 = 12. 19k = 12 + 15 = 27. k = 27/19//