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| 1. |
If the HCF 210 and 55 is expressible in the form 210*5+55y.find y |
| Answer» First, find the HCF of 210 and 55 by Euclid\'s Division Algorithm 210 = 55\xa0{tex}\\times{/tex} 3 + 4555 = 45\xa0{tex}\\times{/tex} 1 + 1045 = 10\xa0{tex}\\times{/tex} 4 + 510 = 5\xa0{tex}\\times{/tex} 2 + 0 (zero remainder)therefore, HCF (210 , 55) = 5Now,{tex}\\therefore {/tex}{tex}5 = 210 \\times 5 + 55y{/tex}{tex} \\Rightarrow {/tex}{tex}5 - 1050 = 55y{/tex}{tex} \\Rightarrow {/tex}{tex} - 1045 = 55y{/tex}{tex} \\Rightarrow {/tex}{tex}y = - 19{/tex} | |