If the HCF of 210 and 55 is expressible in the form 210×5+55y then fi

1.	If the HCF of 210 and 55 is expressible in the form 210×5+55y then find y
Answer» HCF of 210&55 is 5According to the question5=210*5+55y5=1050+55y-1045=55yY=-1045/55Y=-209/11

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