If the HCF of 210 and 55 is expressible in the form 210 multiply 5 add

1.	If the HCF of 210 and 55 is expressible in the form 210 multiply 5 add 55 y , find y
Answer» Let us first find the HCF of 210 and 55.Applying Euclid division lemna on 210 and 55, we get210 = 55 × 3 + 4555 = 45 × 1 + 10\xa045 = 4 × 10 + 5\xa010 = 5 × 2 + 0\xa0We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55.∴ 5 = 210 × 5 + 55y⇒ 55y = 5 - 1050 = -1045∴\xa0y = -19

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