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| 1. |
If the LCM and hcf of two numbers is 1260 and their LCM is 900 more than their hcf |
| Answer» Let the HCF be xLCM=HCF+900LCM=x+900 --(1)And\xa0LCM+HCF=1260LCM+x=1260 --(2) From (1) and (2)(x+900)+x=12602x+900=12602x=1260−9002x=360x=2360\u200bx=180HCF\xa0=180And, from (1),LCM=HCF+900LCM=180+900LCM=1080By formula, product of the numbers is equal to the product of their HCF and LCM.Product of numbers\xa0=HCF×LCM =180×1080Product\xa0=194400 | |