If the median of the series exceeds the mean by 3, find by what number the mode exceeds its mean?

If the median of the series exceeds the mean by 3, find by what number

1.	If the median of the series exceeds the mean by 3, find by what number the mode exceeds its mean?
Answer» 3(median) = 2(mean) + modeLet the mean be \'x\'So, median will be x + 3Then, according to the question3(x+3) = 2(x) + mode3x + 9 = 2x + mode3x - 2x + 9 - modex+9 = modeNow, mode - mean⇒ x+9 - x= 9 So, mode exceeds the mean by 9. \xa0