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If the numbers n-2,4n-1 and 5n+2 are in ap then find the value of n

Answer» We know that if a, b and c are in AP thena+c/2=bSo, (n-2)+(5n+2)/2=4n-16n/2=4n-13n=4n-14n-3n=1n=1And the numbers are n-2=1-2=-1,4n-1=4(1)-1=3,and5n+2=5(1)+2=7


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