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If the points A(k+1, 2k), B(3k, 2k+3) and C(5k -1, 5k) are collinear, then findthe value of k. |
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Answer» Sorry K=2 and K=1/2 Its simple , it is given that all three points are collinear i.e. area of points A,B&C is zero. So by putting formula: Area of points A,B&C =1/2 [X1 (Y2-Y3) + X2 (Y3-Y1) + X3 (Y1-Y2)]Where ,Area=0, X1=(k+1), X2=3k, X3=(5k-1), Y1=2k, Y2=(2k+3), and Y3=5k.We get X=2 and X=1/2.. |
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