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If the probability of incorporation of a gene A from a bacterial cell that has lysed in the medium is a. And the probability of incorporation of another gene B from the same bacteria that has lysed is b. What is the probability of one recipient receiving both?(a) a+b(b) a-b(c) a X b(d) a/bThe question was posed to me in semester exam.Query is from Gene Mapping in Bacteria by Transformation topic in portion Genomics : The Mapping and Sequencing of Genomes of Cytogenetics

Answer»

The correct answer is (c) a X b

Easiest explanation: For both GENES to be incorporated together we must MULTIPLY the PROBABILITY of incorporation of either genes. Thus, the probability value overall DECREASES.



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