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If the product of the zeros of the polynomial 3x square +5x -4k is -8,then find the value of k

Answer» put x = -8\xa0in\xa0{tex}3x^2 + 5x - 4k = 0{/tex}{tex}3(-8)^2 + 5(-8)-4k = 0\xa0{/tex}{tex}3(-8)^2 + 5(-8)\xa0- 4 k = 0{/tex}\xa0192 - 40 - 4k\xa0= 0152 = 4k{tex}\\Rightarrow{/tex}\xa0k =\xa028{tex}\\therefore{/tex}\xa0k = 28


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