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If the pth, qth and rth terms of an A.P. are a, b, c respectively, prove that a(q – r) + b (r – p) + c(p – q) = 0. |
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Answer» Let A be the first term and D be the common difference of A.P. ap = a, ∴ A + (p – 1)D = a ….. (1) aq = b, ∴ A + (q – 1)D = b ……. (2) ar = c, ∴ A + (r – 1)D = c …….. (3) ∴ a (q – r) + b (r – p) + c (p – q) = [A + (p – l) D] (q – r) + [A + (q – 1) D] (r – p) + [A + (r – 1) D] (p – q) [Using (1), (2) and (3)] = (q – r + r – p + p – q)A + [(p – l)(q – r) + (q – l)(r – p) + (r – l)(p – q)]D = (0) A + (pq – pr – q + r + qr – pq – r + p + pr – p – qr + q)D = (0)A + (0)D = 0. |
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