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Write the first six terms of the sequences given by (i) a1 = a2 = 1 = an - 1 + an - 2 (n ≥ 3)(ii) a1 = 4, an + 1 = 2nan |
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Answer» (i) Here a1 = a2 = 1 = an - 1 + an - 2 (n ≥ 3) Putting n = 3, a3 = a2 + a1 = 1 + 1 = 2 Putting n = 4, a4 = a3 + a2 = 2 + 1 = 3 Putting n = 5, a5 = a4 + a2 = 3 + 2 = 5 Putting n = 6, a6 = a5 + a4 = 5 + 3 = 8 ∴ First six terms of the sequence are 1, 1, 2, 3, 5, 8 (ii) Here a1 = 4 and an + 1 = 2nan Putting n = 1, a2 = 2 × 1 × a1 = 2 × 1 × 4 = 8 Putting n = 2, a3 = 2 × 2 × a2 = 4 × 8 = 32 Putting n = 3, a4 = 8 × 192 = 1536 Putting n = 4, a5 = 2 × 4 × a4 = 8 × 192 = 1536 Putting n = 5, a6 = 2 × 5 × a5 = 10 × 1536 = 15360 |
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