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If C0, C1, C2,… Cn are coefficients of expansion (1 + x)n then find the value of :(i) 8C1 + 8C2 + 8C3 + … + 8C8(ii) 8C1+ 8C3 + 8C5 + 8C7 |
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Answer» (i) 8C1 + 8C2 + 8C3 + … + 8C8 We know that nC0 + nC1+ nC2 + … + nCn = 2n Putting n = 8 8C0 + 8C1 + 8C2 + …. + 8C8 = 28 ⇒ 1 +8C1 + 8C2 + 8C3 + … + 8C8 = 28 ⇒ 8C1 + 8C2 + …. + 8C8 = 28 – 1 = 255. (ii) 8C1 + 8C3 + 8C5 + 8C7 We know that 8C1 + 8C3 + 8C5 +… = 2n-1 Putting n = 8 8C1 + 8C3 + 8C5 + 8C7 = 28 -1 = 27 = 128. |
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