1.

Write the number of terms in the expansion of (1-3x+3x2-x3)8.

Answer»

Given :

(1-3x+3x2-x3)8

Highest power is (x3)8 = x24

And lowest power is x0

So the expansion contains all the terms ranging from 0 to 24 

Therefore,

Total number of terms = 25



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