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If (1 + x) n = C0 + C1x + C2x2 + .... + Cnxn, then C0 + 3 . C1 + 5 . C2 + .... + (2n + 1) . Cn equals(a) 22n–1 (b) (n + 1) 2n (c) n . 2n+1 (d) (n – 1) 2n–1 |
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Answer» Answer : (b) (n + 1) 2n C0 + 3C1 + 5C2 + ..... (2n + 1) Cn = (C0 + C1 + C2 + ..... + Cn) + (2C1 + 4C2 + ..... + 2n Cn) = 2n + 2 (C1 + 2C2 + 3.C3 + ..... + n Cn) = 2n + 2 × n . 2n–1 = 2n + n . 2n = 2n (n + 1). |
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