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| 1. |
If the pth term of AP is q and qth term is p.Then show that its nth is ( p+q-n). |
| Answer» ap= a+(q-1)d.......(i) and aq=a+(p-1)d.....(ii) now, solve eq. i and ii yu will get, d=-1..... substitute the value in i or ii yu will get a=p+q-1..... now an=a+(n-1)d... put values of a and d | |