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If the quadratic equation(k+1)x-2(k-1)x+1= 0have real and equal roots then find the value of k

Answer» D=b2 - 4ac=0(k-1)2 - 4/k+1=0(k-1)2 = 4(k+1)k2 - 2k+1 = 4k+4k2 - 6k -3=0there appears to some error in the qn please check and resubmit , thanks


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