If the quadratic equation px^2-2√5px+15=0 has two equal roots,then f

1.	If the quadratic equation px^2-2√5px+15=0 has two equal roots,then find the value of p.
Answer» Given quadratic equation is, px² -2√5 px + 15 = 0Compare px² -2√5 px + 15 = 0 with ax² + bx + c = 0a = p , b = -2√5p , c = 15We know that , If the roots of the quadratic equation are equal , then it\'s discriminant (D) equals to zero.discriminant = 0b² - 4ac = 0( -2√5 p )² - 4× p × 15 = 020p² - 60p = 020p ( p - 3 ) = 0p - 3 = 0p = 3\xa0\xa0\xa0\xa0\xa0

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