If the quadratic equation px^2 - 2 root5 px +15=0 then find the value

1.	If the quadratic equation px^2 - 2 root5 px +15=0 then find the value of p
Answer» We have, px2\xa0-\xa0{tex}2\\sqrt{5}{/tex}px + 15 = 0\xa0Since the roots of equation are equal. Then,Discriminant, D = 0{tex}\\Rightarrow{/tex}\xa0({tex}2\\sqrt{5}{/tex}p)2\xa0- 4(p)(15) = 0{tex}\\Rightarrow{/tex}\xa020p2\xa0- 60p = 0{tex}\\Rightarrow{/tex}\xa020p(p -3) = 0{tex}\\Rightarrow{/tex}\xa020p = 0 or p - 3 = 0{tex}\\Rightarrow{/tex}\xa0p = 3 [since p\xa0{tex}\\neq{/tex}\xa00]

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