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If the radii of end is the bucket are 5cm and 15 cm with 24cm High,then curved surface area is. |
| Answer» Height of bucket = 24 cm (h)Radius of upper end = 15 cm (R)Radius of lower end = 5 cm (r)Slant height of frustum{tex}l = \\sqrt { h ^ { 2 } + ( R - r ) ^ { 2 } }{/tex}{tex}\\Rightarrow \\quad l = \\sqrt { ( 24 ) ^ { 2 } + ( 15 - 5 ) ^ { 2 } } {/tex}{tex}\\Rightarrow \\quad l = \\sqrt { 576 + 100 }{/tex}{tex}\\Rightarrow \\quad l = \\sqrt { 676 }{/tex}\xa0= 26 cmTherefore, Surface area of bucket =\xa0{tex}\\pi l ( R + r ) {/tex}=\xa0{tex}\\pi \\times 26 ( 15 + 5 ) {/tex}{tex}= \\pi \\times 520{/tex}= 520{tex}\\pi{/tex}\xa0cm2 | |