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If the sides of the right angled triangle is x+2, x+1, x then what is the value of x?(a) 1(b) 2(c) 3(d) 4I had been asked this question during an interview.Question is taken from Solution of Quadratic Equation by Factorisation topic in chapter Quadratic Equation of Mathematics – Class 10

Answer»

The CORRECT option is (a) 1

Explanation: SIDES of the right angled triangle is X+2, x+1, x

From Pythagoras THEOREM,

hyp^2=adj^2+base^2

(x+2)^2=(x+1)^2+(x)^2

x^2+4x+4=x^2+1+2x+x^2

4x+4=x^2+1+2x

x^2-2x-3=0

x^2+3x-x-3=0

x(x+3)-1(x+3)=0

(x-1)(x+3)=0

x=1, -3

Since, sides of triangle cannot be negative.

Hence, x=1


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