if the sin o = 3/5, what is the value of 3 cot o

1.	if the sin o = 3/5, what is the value of 3 cot o
Answer» If\xa0sino = 3/5Then, opposite side of the right angled triangle containing angle\xa0o = 3 and hypotenuse\xa0=5Using pythagoras theorem, we get the adjacent side\xa0= 4\xa0Now we have, coso =Adjacent\u200b/Hypotenuse=4/5 \u200bAnd cot o =Adjacent/Opposite\u200b= 3/43 cot o =3( 3/4) = 9/4

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