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If the sum of 3 number in AP be 24 and their product is 440 find their no |
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Answer» Let No. Be (a-x) (a) (a+x)a-x+a+a+x=24a=8 (a-x) (a) (a+x)=440Put value of aThen,xsquare = 9X=3No.\'s are 8-3=5,8,8+3=11 answer Let the three numbers be a, a+d, a+2da+a+d+a+2d=243a+3d=24a+d=8d=8-a--------(i)a(a+d)(a+2d)=440a(8)(a+d+d)=4408a(8+d)=4408a(8+8-a)=4408a(16-a)=440128a-8a2=4408a2-128a+440=0a2-16a+55=0(÷by 8)a2-11a-5a+55=0a(a-11)-5(a-5)=0(a-11)(a-5)=0a-11=0 or, a-5=0a=11 or a=5If a =11, d=8-11=-3If a=5, d=8-5=3So the numbers are 11,8,5or, 5,8,11 |
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