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If the sum of first 14 terms of an A•P is 1050 and its first term is 10 find the 20 term

Answer» A=10...givenS14=1050⇒ n/2[2a+(n-1)d]=1050⇒ 14/2[20+13d]=1050⇒ 7[20+13d]=1050⇒ 20+13d=1050/7⇒ 20+13d=150⇒ 13d=150-20⇒ 13d=130⇒ d=1020th term = a+19d = 10 + 19×10 = 10 + 190 = 200\xa0


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