If the sum of first n terms of an ap is n2\xa0find the 5th\xa0term of

1.	If the sum of first n terms of an ap is n2\xa0find the 5th\xa0term of the ap\xa0
Answer» {tex}sum\\,of\\,first\\,n\\,terms\\,{S_n} = {n^2}{/tex}{tex}nth\\,term\\,{a_n} = {S_n} - {S_{n - 1}}{/tex}{tex} = {n^2} - {\\left( {n - 1} \\right)^2}{/tex}{tex} = {n^2} - \\left( {{n^2} - 2n + 1} \\right){/tex}{tex} = 2n - 1{/tex}{tex}5th\\,term\\,{a_5} = 2 \\times 5 - 1 = 9{/tex}\xa0

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