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If the sum of two numbers are 18 and sum of their squares are 290,then find the numbers |
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Answer» The numbers in case 1and case 2 should be same x + y = 18let x be 18-yso,(18-y)² + y² = 29018²+ y² - 36y + y² = 2902y² - 36y = -342y² - 36y +34 = 0solving the equationy² -34y-2y+68 = 0y(y-34) -2( y-34) = 0(y-2) (y-34) = 0so,y= 2 or 34case 1,y =2 and x = 16case 2y = 34x = -16 |
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