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If the sum ofthe zeroes of the quarduatic polynomial ky+2y-3k equal to twice thier product find k

Answer» p(y) = ky2 + 2y - 3kCompare p(y) with standard form ax2 + bx + ca = k, b = 2, c = -3kAccording to question,Sum of zeroes = 2(Product of zeroes){tex}\\Rightarrow \\quad \\frac { - b } { a } = 2 \\times \\frac { c } { a }{/tex}{tex}\\Rightarrow \\frac { - 2 } { k } = 2 \\times \\frac { - 3 k } { k }{/tex}{tex}\\Rightarrow \\quad \\frac { 2 } { k } = 6{/tex}{tex} \\Rightarrow k = \\frac { 1 } { 3 }{/tex}


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