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If the system of equations `x-k y-z=0, k x-y-z=0,x+y-z=0`has a nonzero solution, then the possible value of `k`are`-1,2`b. `1,2`c. `0,1`d. `-1,1`A. `-1, 2`B. `1, 2`C. 0, 1D. `-1, 1` |
Answer» Correct Answer - D The given system of equations has non-zero i.e., non -trivial solution `:. |(1,-k,-1),(k,-1,-1),(1,1,-1)|= 0` `rArr|(1,-k,-1),(k -1,-1 +k,0),(0,1 +k,0)| = 0 " " [("Applying " R_(2) rarr R_(2) - R_(1)),(and R_(3) rarrR_(3) - R_(1))]` `rArr - (k^(2) -1) = 0 rArr k = +- 1` |
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