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If the third and the ninth term of an AP are 4 and 8 respectively,which term of this AP is 0? |
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Answer» Yogita a great job... an\u200b=a+(n−1)da3\u200b=4=a+2d\xa0....(1)a9\u200b=−8=a+8d\xa0....(2)∴4−2d=−8d−8−2d+8d=−8−46d=−12d=−2\u200ba=4−2d=4+4=8an\u200b=0,a=8,d=−20=8+(n−1)×(−2)0=8−2n+22n=10n=5 |
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