Saved Bookmarks
| 1. |
If the zeros of the polynomial f(x)= x^3-3x^2+x+1 are (a-b), a and (a+b), find a & b. |
|
Answer» Prakash 13:33Hey, glad to know that you\'re learning from BYJU\'S. For more help you may chat here.Student 13:33If the zeros of the polynomial f(x)= x^3-3x^2+x+1 are (a-b), a and (a+b), find a & b.ReadNew messagePrakash 13:34Kindly allow me a minute or two to check for relevant answers to your question. Please be online.Prakash 13:35ANSWERa−b,a,a+b are zeroes of x3−3x2+x+1⇒a−b+a+a+b= sum of zeroes = 3⇒3a=3⇒a=1(a−b)(a)(a+b)= product of zeroes =−1⇒(1−b)(1+b)=−1⇒1−b2=−1⇒b2=2⇒b=±2\u200b sum of the zeroes = (a-b) + (a+b) + a = 3a i.e. 3a = - b/a or 3a=3 or a=1product of the zeroes = (a-b)*(a+b)*a= a3-ab2 i.e. 1 - b2\xa0= c/a (by putting the value a=1) or b2\xa0=2 or b = +-root2 |
|