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| 1. |
If thita =1√7 then find cosec^2thita-sin^2thita/cosec^2thita+sec^2thita? |
| Answer» Take X=thetatan X=1/√7sec^2x=1+1/7=8/7Cos^2x=7/8Sin^2x=1-7/8=1/8 ,cosec^2x=8/1So the expression is=8/1-(1/8)/(8)+8/7=8/1-1/64+8/7=(3584-7+512)/64=4089/64=63.89\xa0 | |